A) 1 m/s
B) 5 m/s
C) 7 m/s
D) 10 m/s
Correct Answer: B
Solution :
Distance convered towards east \[=2\times 15\,=30\,m\] Distance covered towards north \[=8\times 5\,=40\,m\] Total displacement\[=\sqrt{{{40}^{2}}+{{30}^{2}}}=50\,m\] Average velocity\[\text{=}\frac{\text{total}\,\text{displacement}}{\text{total}\,\text{time}}\] \[=\frac{50}{2+8}=5\,m/s\]You need to login to perform this action.
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