A) \[1-Butene\]
B) \[2-Butene\]
C) \[1-Butanol\]
D) \[2-Butaneol\]
Correct Answer: A
Solution :
\[\underset{1-\text{chloro}\,\text{butane}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}C{{H}_{2}}Cl}}\,\xrightarrow{Alc\,KOH}\] \[\underset{1-\text{butane}}{\mathop{C{{H}_{3}}C{{H}_{2}}}}\,-CH=C{{H}_{2}}\]You need to login to perform this action.
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