A) 0.215 m
B) 0.125 m
C) 1 m
D) 0.5 m
Correct Answer: D
Solution :
Wavelength\[\lambda =\frac{\upsilon }{n}\] \[=\frac{330}{660}=\frac{1}{2}=0.5\,m\] For maximum amplitude, distance should be 0.5 m.You need to login to perform this action.
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