A) 5.6m/s
B) 11.2m/s
C) 22.4 km/s
D) 44.2 m/s
Correct Answer: C
Solution :
Escape velocity from earths surface\[{{\upsilon }_{p}}=\sqrt{2{{g}_{p}}{{R}_{p}}}\] Escape velocity from planet \[{{\upsilon }_{p}}\,=\sqrt{2{{g}_{p}}{{R}_{p}}}\] \[\begin{align} & =\sqrt{2(2g)(2\operatorname{Re})=2{{\upsilon }_{e}}} \\ & =2\times 11.2=22.4\,km/s \\ \end{align}\]You need to login to perform this action.
You will be redirected in
3 sec