A) \[{{10}^{-4}}m\]
B) \[{{10}^{-3}}mm\]
C) 10-4\[\times \pi m\]
D) \[\pi \times \]10-3m
Correct Answer: B
Solution :
\[a=0.3,\alpha =1{}^\circ ,\mu =1.54\] \[d=2a(\mu -1)\alpha \] \[\begin{align} & =2\times 0.3(1.54-1)\times 1 \\ & =2\times 0.3\times 0.54=0.324 \\ \end{align}\] Fringe width \[=\beta =\frac{D\lambda }{d}\] \[=\frac{0.7\times 180\pi \times {{10}^{-9}}}{0.324}\] \[=\frac{7\times 18\pi \times {{10}^{-6}}}{324}={{10}^{-3}}mm\]You need to login to perform this action.
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