A) does not change
B) forward
C) backward
D) decrease
Correct Answer: A
Solution :
\[{{H}_{2(g)}}+{{I}_{2(g)}}2H{{I}_{(g)}}\] The equilibrium in the formation of \[HI\] from \[{{H}_{2}}\]and 12 is not affected by the increase in pressure because there is no change in the number of moles i.e., the number of moles of reactants and products is the same.You need to login to perform this action.
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