A) increases
B) decreases
C) zero
D) does not change
Correct Answer: A
Solution :
In a hybrid orbital, s-character increases bond angle increases. e.g., Bond angle of, \[s{{p}^{3}}<s{{p}^{2}}<sp\]\[25%\text{ }33%\text{ }50%\]s-characterYou need to login to perform this action.
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