A) 750 rad
B) 1500 rad
C) 3000 rad
D) 6000 rad
Correct Answer: A
Solution :
\[t=I\,\alpha \] \[30=2\times \alpha \] \[\Rightarrow \] \[\alpha =15\,rad/{{\sec }^{2}}\] From equation of angular motion \[\,\text{=}{{\omega }_{0}}t+\frac{1}{2}\alpha {{t}^{2}}\] \[\begin{align} & \,\text{=}\,\text{0}+\frac{1}{2}\times 15\times 10\times 10 \\ & =750\,\text{rad} \\ \end{align}\]You need to login to perform this action.
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