A) 20
B) 10
C) 40
D) 15
Correct Answer: B
Solution :
\[\mu =18,{{R}_{P}}=8000\,\Omega ,\]\[{{R}_{L}}=10,000\,\Omega \] Voltage amplification \[A=\frac{\mu {{R}_{L}}}{{{R}_{P}}+{{R}_{L}}}\] \[=\frac{18\times 10,\,000}{8000+10,\,000}\] \[=\frac{18\times 10,000}{18000}=10\]You need to login to perform this action.
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