A) 2/3 ohm
B) 5/ ohm
C) 8/9 ohm
D) 7.5 ohm
Correct Answer: D
Solution :
The figure can be shown as equivalent resistance of \[{{R}_{1}},\]\[{{R}_{2}}\]and\[{{R}_{3}}\] \[R={{R}_{1}}+{{R}_{2}}+{{R}_{3}}\] \[=5+5+5=15\,\Omega \] Equivalent resistance of\[{{R}_{4}}{{R}_{5}}\] and \[{{R}_{6}}\] \[\begin{align} & R=5+5+5=15\Omega \\ & {{R}_{AB}}=\frac{RR}{R+R} \\ \end{align}\] \[=\frac{15\times 15}{15+15}=\frac{15}{2}=7.5\,\text{ohm}\]You need to login to perform this action.
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