A) repulsion between \[1p\] and bond pair
B) \[s{{p}^{3}}\]-hybridization of O
C) H-bonding
D) higher electronegativity of O
Correct Answer: A
Solution :
In \[{{H}_{2}}O\] molecule, although central O atom is \[s{{p}^{3}}\]hybridized, \[H-O-H\]bond angle should be \[{{109}^{o}}\,28,\]but the angle is\[{{104}^{o}}\text{ }31\]. The decrease is bond angle is due to the repulsion between lone pairs present on O atom and bond pairs.You need to login to perform this action.
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