A) \[s{{p}^{3}}-s{{p}^{3}}\]
B) \[s{{p}^{3}}-s{{p}^{2}}\]
C) \[sp-s{{p}^{2}}\]
D) \[sp-s{{p}^{3}}\]
Correct Answer: C
Solution :
\[HC\equiv \underset{sp}{\mathop{C}}\,-\underset{s{{p}^{2}}}{\mathop{HC}}\,=C{{H}_{2}}\] Hybridisation \[C-C\]single bond is \[sp-s{{p}^{2}}\].You need to login to perform this action.
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