A) \[C{{H}_{3}}C{{H}_{2}}-C{{H}_{2}}-CH=C{{H}_{2}}\]
B) \[C{{H}_{3}}-C{{H}_{2}}-C\equiv CH\]
C) \[{{(C{{H}_{3}})}_{2}}CH-C\equiv CH\]
D) \[C{{H}_{2}}=CH-C{{H}_{2}}-CH=C{{H}_{2}}\]
Correct Answer: C
Solution :
Compound is \[{{(C{{H}_{3}})}_{2}}CH-C\equiv CH\] \[{{(C{{H}_{3}})}_{2}}CH-C\equiv CH-AgN{{O}_{3}}+N{{H}_{4}}OH\xrightarrow{{}}\] \[\underset{(White\,ppt)}{\mathop{{{(C{{H}_{3}})}_{2}}CH}}\,-C\equiv CH-AgN{{O}_{3}}+N{{H}_{4}}N{{O}_{3}}+{{H}_{2}}O\] \[{{(C{{H}_{3}})}_{2}}CH-C\equiv CH+[O]\xrightarrow[KMn{{O}_{4}}/KOH]{Hot}\] \[{{(C{{H}_{3}})}_{2}}CH-COOH\]You need to login to perform this action.
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