A) \[R=nr\]
B) \[R=\frac{r}{n}\]
C) \[R={{n}^{2}}r\]
D) \[R=r\]
Correct Answer: D
Solution :
Current when cells are connected in series \[{{i}_{s}}=\frac{nE}{nr+R}\] In parallel \[{{i}_{P}}=\frac{nE}{r+nR}\] According to question \[{{i}_{s}}={{i}_{p}}\] \[\frac{nE}{nr+R}=\frac{nE}{r+nR}\] \[r+nR=nr+R\] \[(n-1)R=r(n-1)\] \[\Rightarrow \] \[R=r\]You need to login to perform this action.
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