A) \[10\,cm\]
B) \[10\,\sqrt{2}\,cm\]
C) \[5\,\sqrt{2}\,cm\]
D) \[20\,cm\]
Correct Answer: B
Solution :
When capillary tube is tilted through an angle \[\text{,}\] then length of water risen in capillary, \[l=\frac{h}{\cos \,}\] Here \[=45{}^\circ \] \[\therefore \] \[l=\frac{10}{\cos \,45{{{}^\circ }^{-}}}10\sqrt{2}cm\]You need to login to perform this action.
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