A) \[mg\]
B) \[emg\]
C) \[\frac{mg}{e}\]
D) \[\frac{em}{g}\]
Correct Answer: C
Solution :
For equilibrium of charged drop, upward electric force = downward weight \[eE=mg\] \[\Rightarrow \]Electric field, \[E=\frac{mg}{e}\]You need to login to perform this action.
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