A) 512 Hz
B) 256 Hz
C) 128 Hz
D) 1024 Hz
Correct Answer: D
Solution :
For a closed pipe, fundamental frequency, \[n=\frac{v}{4l}=512Hz\] For an open pipe, fundamental frequency, \[n=\frac{v}{2l}=2\times \left( \frac{v}{4l} \right)\] \[=2\times 512\,Hz=1024\,Hz\]You need to login to perform this action.
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