A) \[C{{H}_{3}}C{{H}_{2}}CHO\]
B) \[C{{H}_{3}}COC{{H}_{3}}\]
C) \[C{{H}_{3}}CHOHC{{H}_{3}}\]
D) \[C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}OH\]
Correct Answer: A
Solution :
Molecular \[wt.=2\times vapour\text{ }density\] \[=2\times 29=58\] Two compounds \[C{{H}_{3}}COC{{H}_{3}}\]and \[C{{H}_{3}}C{{H}_{2}}\text{ }CHO\]show molecular weight 58. \[C{{H}_{3}}COC{{H}_{3}}\]do not produce yellow precipitate on warming with aq. Solution of\[NaOH\]. Hence \[C{{H}_{3}}C{{H}_{2}}CHO\]is the compound.You need to login to perform this action.
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