A) \[\Delta H=\Delta E-RT\]
B) \[\Delta H=\Delta E-2RT\]
C) \[\Delta H=\Delta E+2RT\]
D) \[\Delta H=\Delta E+RT\]
Correct Answer: B
Solution :
For the reaction \[{{N}_{2}}+3{{H}_{4}}\xrightarrow{{}}2N{{H}_{3}}\] Number of gaseous molecules (n) \[=2-4=-2\] \[\because \] \[\Delta H=\Delta E+nRT\] \[\Delta E+(-2)RT\] (\[\because \] \[n=-2\]) \[\therefore \] \[\Delta H=\Delta E-2RT\]You need to login to perform this action.
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