A) R
B) 2R
C) \[\frac{R}{2}\]
D) 6/R
Correct Answer: A
Solution :
The given circuit (between A and B) is a balanced Wheat stones bridge. Therefore resistance between C and D is ineffective. So, equivalent current is shown in figure. The resistances 2R and 2R are in parallel, so, effective resistance \[{{R}_{eff}}=\frac{{{R}_{1}}{{R}_{2}}}{{{R}_{1}}+{{R}_{2}}}\] \[=\frac{2R\times 2R}{2R\times 2R}=R\]You need to login to perform this action.
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