A) \[{{I}_{0}}\]
B) \[\frac{{{I}_{0}}}{2}\]
C) \[\frac{{{I}_{0}}}{4}\]
D) zero
Correct Answer: B
Solution :
When unpolarised light passes through a polarbid, intensity of emergent light, \[I={{I}_{0}}{{({{\cos }^{2}})}_{mean}}\] \[={{I}_{0}}\times \frac{1}{2}=\frac{{{I}_{0}}}{2}\]You need to login to perform this action.
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