A) 1-butyne
B) 1-butene
C) 1-butane
D) 3-butane
Correct Answer: A
Solution :
\[\underset{Ethylbromide}{\mathop{C{{H}_{3}}C{{H}_{2}}}}\,+\underset{sodium\,acetylide}{\mathop{Br+Na\,\,C\equiv CH}}\,\xrightarrow{{}}\] \[\underset{1-butyne}{\mathop{C{{H}_{3}}C{{H}_{2}}C\equiv CH+NaBr}}\,\]You need to login to perform this action.
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