A) neutron
B) proton
C) electron
D) positron
Correct Answer: B
Solution :
According to question reaction may be expressed as \[_{2}H{{e}^{4}}{{+}_{7}}{{N}^{14}}{{\xrightarrow{{}}}_{8}}{{O}^{17}}+{{ & }_{1}}{{X}^{1}}\] (proton) So, particle X is a proton (1H1)You need to login to perform this action.
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