A) \[{{\tan }^{-1}}(1/\pi )\]
B) \[{{\tan }^{-1}}(1/2\pi )\]
C) \[{{\tan }^{-1}}(\pi /2)\]
D) \[{{\tan }^{-1}}(2\pi /2)\]
Correct Answer: A
Solution :
Let the angle between current and source voltage is\[\phi \] \[\therefore \] \[\tan \phi =\left( \frac{1}{\omega CR} \right)\] or \[\tan \phi {{\tan }^{-1}}\left( \frac{1}{\omega CR} \right)\] Hence: \[\omega =2\pi f=2\pi \times 50=100\pi \,rad/\sec \] \[\begin{align} & C=100\mu F=100\times {{10}^{-6}}F=1\times {{10}^{-4}}F \\ & R=100\,\Omega \\ \end{align}\] Therefore, \[\phi ={{\tan }^{-1}}\left( \frac{1}{100\mu \times {{10}^{-4}}\times 100} \right)\] \[={{\tan }^{-1}}\left( \frac{1}{\pi } \right)\]You need to login to perform this action.
You will be redirected in
3 sec