RAJASTHAN PMT Rajasthan - PMT Solved Paper-2003

  • question_answer
    The work function of a photometal is 6.63 eV. The threshold wavelength is

    A)  \[3920\,\overset{o}{\mathop{\text{A}}}\,\]                                      

    B)  \[1866\,\overset{o}{\mathop{\text{A}}}\,\]

    C)  \[186.6\,\overset{o}{\mathop{\text{A}}}\,\]                    

    D)         \[18666\,\overset{o}{\mathop{\text{A}}}\,\]

    Correct Answer: B

    Solution :

    Work function of a photometal, \[W=\frac{hc}{{{}_{0}}}\]where\[{{\lambda }_{0}}\] is threshold wavelength,                                 \[\therefore \,\,\,\,\,\,\,\,\,{{\lambda }_{0}}\,=\frac{hc}{W}\]                                   \[\begin{align}   & =\frac{12375}{(W\,in\,eV)}=\frac{12375}{6.63}\overset{{}^\circ }{\mathop{\text{A}}}\, \\  & =1866\overset{{}^\circ }{\mathop{\text{A}}}\, \\ \end{align}\]


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