A) \[0.01\]
B) \[0.1\]
C) \[10\]
D) \[100\]
Correct Answer: A
Solution :
\[{{N}_{2}}+{{O}_{2}}2NO\] \[{{K}_{p}}=\frac{P_{No}^{2}}{{{P}_{{{N}_{2}}}}.{{P}_{{{O}_{2}}}}}\] ?.(i) \[2NO{{N}_{2}}+{{O}_{2}}\] \[K_{P}^{}=\frac{{{P}_{{{N}_{2}}}}.{{P}_{{{O}_{2}}}}}{P_{NO}^{2}}\] ??(ii) From equation (i) and (ii), we have \[K_{P}^{}=\frac{1}{{{K}_{P}}}=\frac{1}{100}=0.01\]You need to login to perform this action.
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