A) 448 Hz
B) 455 Hz
C) 440 Hz
D) 468 Hz
Correct Answer: D
Solution :
Apparent frequency heard by stationary observer\[n=n\left( \frac{\upsilon }{\upsilon ={{\upsilon }_{s}}} \right)\] Here: \[\upsilon \] = 330 m/sec, \[{{\upsilon }_{s}}\] = 20 m/s \[n=440\,Hz\] \[\therefore \] \[n=440\left( \frac{330}{330-20} \right)\] \[\begin{align} & =468.38 \\ & \approx 468Hz \\ \end{align}\]You need to login to perform this action.
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