A) 25g
B) 15 g
C) 10 g
D) 6.25g
Correct Answer: D
Solution :
\[\frac{M}{{{M}_{0}}}={{\left( \frac{1}{2} \right)}^{t/{{T}_{1/2}}}}\] Here : \[{{M}_{0}}=100g,t=16\]days, \[{{T}_{1/2}}=4\]days From eq (1), we get \[\therefore \] \[M=100{{\left( \frac{1}{2} \right)}^{16/4}}\] \[=100\times {{\left( \frac{1}{2} \right)}^{4}}=100\times \frac{1}{16}=6.25g\]You need to login to perform this action.
You will be redirected in
3 sec