A) 4, 0
B) 3, 6
C) 3, 2
D) 2, 1
Correct Answer: C
Solution :
Nuclear reaction can be shown as \[_{90}{{X}^{232}}\xrightarrow{{{n}_{2}}H{{e}^{4}}}\Upsilon {{\xrightarrow{n1{{\beta }^{0}}}}_{86}}{{M}^{220}}\] Since, atomic mass and atomic number remain conserved in nuclear reaction, so, \[90=2n+(-n)+86\] \[\Rightarrow \] \[2n=n=4\] ?(i) and \[232=4n+0+220\] \[\Rightarrow \] \[4n=12\] \[\therefore \] \[n=3\] Substituting the value of n in equation (i), we get \[2\times 3-n=4\] \[\Rightarrow \] \[n=6-4=2\] Hence, 3\[\text{-}\]particles and 2p-particles will be disintegrated.You need to login to perform this action.
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