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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2004

  • question_answer
    The energy of first shell in hydrogen is \[13.6\text{ }eV,\]the energy of second shell will be:

    A)  \[3.4eV\]           

    B)         \[10.2\text{ }eV\]

    C)  \[1\,eV\]           

    D)         \[3.02\text{ }eV\]

    Correct Answer: A

    Solution :

    \[E=\frac{13.6}{{{n}^{2}}}=\frac{13.6}{{{(2)}^{2}}}\] \[=\frac{13.6}{4}=3.4eV\]


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