A) \[1\]
B) \[2\]
C) \[3\]
D) \[5\]
Correct Answer: D
Solution :
Oxidation state of \[Mn\]in \[MnO_{4}^{-}=+7\] \[\therefore \]Change in O.S. (equal to number of \[{{e}^{-}}\] involved) \[=7-2=5\] \[\therefore \]Number of Faradays required to reduce Mn04 into \[M{{n}^{2+}}\]+ is 5.You need to login to perform this action.
You will be redirected in
3 sec