A) \[11.04\]
B) \[10.24\]
C) \[6.62\]
D) \[5.48\]
Correct Answer: A
Solution :
From Handersons equation \[pOH{{=}_{p}}{{K}_{b}}+\log \frac{[salt]}{[base]}\] \[=4.75+\log \frac{0.0025/V}{0.15/V}=4.74+\log \frac{1}{60}\] \[=4.74-1.78=2.96\] \[\therefore \] \[pH=14-2.96=11.04\]You need to login to perform this action.
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