A) \[{{C}_{2}}{{H}_{2}}{{O}_{2}}\]
B) \[{{C}_{2}}{{H}_{4}}{{O}_{2}}\]
C) \[C{{H}_{2}}O\]
D) \[{{C}_{2}}{{H}_{4}}{{O}_{6}}\]
Correct Answer: C
Solution :
\[\because \] \[60\,\,g\]of compound contains \[24\,\,g\] of carbon \[\therefore \]\[%\]of carbon\[=\frac{24\times 100}{60}=40%\] Similarly, percentage of hydrogen \[=\frac{4\times 100}{60}=6.66%\] \[\therefore \] percentage of oxygen \[=100-(40+6.66)\] \[=53.34%\]Element | Percentage | Atomic mass | Relative number of atoms | Ratio |
C | \[40%\] | 12 | \[40/12\] \[=3.33\] | \[3.33/3.3\] \[3=1\] |
H | \[6.66%\] | 1 | \[6.66/1\] \[=6.66\] | \[6.66/3.3\] \[3=2\] |
O | \[53.34%\] | 16 | \[53.34/16\] \[=3.33\] | \[3.33/3.3\] \[3=1\] |
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