A) \[+1\]
B) \[+2\]
C) \[+3\]
D) \[-3\]
Correct Answer: B
Solution :
Suppose the oxidation number of sulphur in\[N{{a}_{2}}S{{O}_{3}}\] is\[x\]. \[\therefore \] \[2(+1)+x+3(-2)=0\] \[2+2x-6=0\] \[2x-4=0\] \[\therefore \] \[x=\frac{4}{2}=+2\]You need to login to perform this action.
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