A) more ionization
B) less ionization
C) covalent bond
D) electrovalent bond
Correct Answer: B
Solution :
The \[C{{H}_{3}}COOH\] \[\text{is}\] weaker acid than\[{{H}_{2}}S{{O}_{4}}\]. The reason is that \[C{{H}_{3}}COOH\] is wealky ionized in comparison with\[{{H}_{2}}S{{O}_{4}}\].You need to login to perform this action.
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