A) \[2\sqrt{h(H-h)}\]
B) \[4\sqrt{h(H+h)}\]
C) \[4\sqrt{h(H-h)}\]
D) \[2\sqrt{h(H+h)}\]
Correct Answer: A
Solution :
Applying Bernoullis theorem, the velocity of water at point\[A\] \[v=\sqrt{2\,\,gh}\] Time taken to reach point \[C\] is\[t\] So, \[H-h=\frac{1}{2}g{{t}^{2}}\] \[t=\sqrt{\frac{2(H-h)}{g}}\] Now, horizontal range\[R=vt\] \[\sqrt{gh}\times \sqrt{\frac{2(H-h)}{g}}\] \[=2\sqrt{(H-h)}h\]You need to login to perform this action.
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