A) \[\frac{2}{3}Q\]
B) \[\frac{3}{5}Q\]
C) \[\frac{2}{5}Q\]
D) \[\frac{1}{5}Q\]
Correct Answer: C
Solution :
For monoacomic gas at constant pressure \[\frac{\Delta U}{Q}=\frac{3}{5}\] or \[\Delta U=\frac{3Q}{5}\] Now, applying first law at thermodynamics \[W=\Delta Q-\Delta U\] \[=Q-\frac{3Q}{5}\] \[=\frac{2Q}{5}\]You need to login to perform this action.
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