A) 2.9 cm
B) 3.9 cm
C) 2.35 cm
D) 2 cm
Correct Answer: C
Solution :
The formula for radius of circular path is \[r=\frac{mv}{eB}=\frac{v}{\left( \frac{e}{m} \right)B}\] Given: \[\frac{e}{m}\]of electron \[=1.7\times {{10}^{11}}C/kg,\,\,v=6\times {{10}^{7}}\,\,m/s\] \[B=1.5\times {{10}^{-2}}T\] \[\therefore \] \[r=\frac{6\times {{10}^{7}}}{1.7\times {{10}^{11}}\times 1.5\times {{10}^{-2}}}\] \[=2.35\times {{10}^{-2}}m\] \[=2.35\,\,cm\]You need to login to perform this action.
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