A) \[5I,-3I\]
B) \[9I,I\]
C) \[9I,-I\]
D) \[5I,3I\]
Correct Answer: B
Solution :
During interference intensity obtained, \[{{I}_{0}}={{I}_{1}}+{{I}_{2}}+2\sqrt{{{I}_{1}}{{I}_{2}}}\cos \alpha \] Clearly, \[{{I}_{0}}\] is maximum when\[\cos \alpha =1\]and minimum when\[\cos \alpha =-1\] \[\therefore \] \[{{I}_{\max }}=4I+I+2\sqrt{4I\times I}=9I\] \[{{I}_{\min }}=4I+I-2\sqrt{4I\times I}=I\]
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