A) 0.064%
B) 0.64%
C) 6.4%
D) 6.4%
Correct Answer: C
Solution :
Efficiency of the engine is given by \[e=\left( 1-\frac{{{T}_{2}}}{{{T}_{1}}} \right)\times 100=\left( 1-\frac{273+20}{273+40} \right)\times 100\] \[=\left( 1-\frac{293}{313} \right)\times 100\] \[=0.64\times 100=6.4%\]You need to login to perform this action.
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