A) 0.05 J
B) 1 J
C) 0.005 J
D) 0.1 J
Correct Answer: A
Solution :
Energy stored in the capacitor is \[U=\frac{1}{2}C{{V}^{2}}=\frac{1}{2}\mu F\times {{(100)}^{2}}J\] \[=0.05\,\,J\]You need to login to perform this action.
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