RAJASTHAN PMT Rajasthan - PMT Solved Paper-2007

  • question_answer
    In a DNA perecame fithymine is 20. What is the percentage of guanine?

    A)  20%

    B)                                         40%

    C)  30%                                      

    D)  60%

    Correct Answer: C

    Solution :

    Total DNA (100) = A + T = C + G A = 20% (Given) A = T (Base pairing rule) 100 = 20 + 20 + C + G C + G = 100-40 = 60 C/G = 30 (C = G).


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