A) 40 \[k\,\Omega \]
B) \[4\,k\,\Omega \]
C) 200 \[\,\Omega \]
D) 400 \[\,\Omega \]
Correct Answer: D
Solution :
The term LED is abbreviated as Light Emitting Diode. It is forward-biased \[p-n\] junction which emits spontaneous radiation. Current in the circuit \[=10\,\,mA=10\times {{10}^{-3}}A\] and voltage in the circuit\[=6-2=4\,\,V\]. From Ohms law, \[V=IR\] \[\therefore \] \[R=\frac{V}{I}=\frac{4}{10\times {{10}^{-3}}}=400\Omega \]You need to login to perform this action.
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