A) 13.5 rev/s
B) 1.35 rev/s
C) 0.675 rev/s
D) 6.75 rev/s
Correct Answer: C
Solution :
In circular motion, necessary centripetal force to the man is provided by effective weight of man. Thus, \[m\times 9g=mr{{\omega }^{2}}=mr\times 4{{\pi }^{2}}{{n}^{2}}\] or \[n=\sqrt{\frac{9g}{4{{\pi }^{2}}r}}\] Given, \[r=5\,\,m\] \[\therefore \] \[n=\sqrt{\frac{9\times 10}{4\times {{(3.14)}^{2}}\times 5}}\] 0.675 rev/sYou need to login to perform this action.
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