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RAJASTHAN PMT Rajasthan - PMT Solved Paper-2007

  • question_answer
    \[1.520\,\,g\] of hydroxide of a metal on ignition gave \[0.995\,\,g\] of oxide. The equivalent weight of metal is

    A) \[1.52\]                               

    B)        \[0.995\]

    C)        \[190\]                                 

    D)        \[9\]

    Correct Answer: D

    Solution :

    \[\frac{{{E}_{Hydroxide}}}{{{E}_{metal}}+{{E}_{O{{H}^{-}}}}}>\frac{{{E}_{oxide}}}{{{E}_{metal}}+{{E}_{O}}}\]                 \[\frac{1.520}{E+17}=\frac{0.995}{E+8}\] or            \[E=9\]


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