A) \[C{{H}_{3}}C{{H}_{2}}OH\]
B) \[C{{H}_{3}}-O-C{{H}_{3}}\]
C) \[C{{H}_{3}}C{{H}_{2}}CHO\]
D) \[C{{H}_{2}}=CHOH\]
Correct Answer: D
Solution :
\[HC\equiv CH\xrightarrow[\begin{smallmatrix} HgS{{O}_{4}}/{{H}_{2}}S{{O}_{4}} \\ \,\,\,\,\,\,\,\,\,\,{{60}^{o}}C \end{smallmatrix}]{{{H}_{2}}O}\]You need to login to perform this action.
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