A) \[300\]
B) \[600\]
C) \[900\]
D) \[200\]
Correct Answer: C
Solution :
Molarity of glucose solution \[=\frac{0.5\,\,g}{180\times 1L}=0.00277\,\,M\] Isotonic solution have equal molar concentrations, hence molarity of organic compound solution\[=0.00277\,\,M\] \[\therefore \]Molecular weight of compound \[=\frac{2.5}{0.00277\times 1}=900\]You need to login to perform this action.
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