A) -0.5 J
B) -1.25 J
C) 1.25 J
D) 0.5 J
Correct Answer: B
Solution :
The height \[(h)\] traversed by particle while going up is \[h=\frac{{{u}^{2}}}{2\,\,g}=\frac{25}{2\times 9.8}\] Work done by gravity force\[=m\,\,\overset{\to }{\mathop{\mathbf{g}}}\,\cdot \overset{\to }{\mathop{\mathbf{h}}}\,\] \[=0.1\times g\times \frac{25}{2\times 9.8}\cos {{180}^{o}}\] [Angle between force and displacement is\[{{180}^{o}}\]] \[\therefore \] \[W=-0.1\times \frac{25}{2}=-1.25\,\,J\]You need to login to perform this action.
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