A) \[\,{{L}_{2}},{{L}_{3}}\]
B) \[\,{{L}_{1}},{{L}_{4}}\]
C) \[\,{{L}_{1}},{{L}_{2}}\]
D) \[\,{{L}_{4}},{{L}_{1}}\]
Correct Answer: D
Solution :
Length of tube\[=10\,\,cm\] \[{{f}_{o}}+{{f}_{e}}=10\,\,cm\] Magnification\[m=\frac{{{f}_{o}}}{{{f}_{e}}}=4\] \[{{f}_{o}}=4{{f}_{e}}\] Putting in Eq. (i), \[5{{f}_{e}}=10\,\,cm\] or \[{{f}_{e}}=2\,\,cm\] and \[{{f}_{o}}=8\,\,cm\] \[{{f}_{o}}=8\,\,cm,\,\,{{f}_{e}}=2\,\,cm\] Hence, \[{{L}_{4}}\] and \[{{L}_{1}}\] will be used.You need to login to perform this action.
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