A) 0.180 g
B) 0.141 g
C) 0.126 g
D) 0.242 g
Correct Answer: C
Solution :
According to Faradays law of electrolysis, \[m=zit\] \[\frac{{{m}_{Zn}}}{{{m}_{Cu}}}=\frac{{{z}_{Zn}}}{{{z}_{Cu}}}\] \[\therefore \] \[\frac{0.13}{{{m}_{Cu}}}=\frac{32.5}{31.5}\] \[{{m}_{Cu}}=0.126\,\,g\]You need to login to perform this action.
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